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x^2+x=3.809
We move all terms to the left:
x^2+x-(3.809)=0
We add all the numbers together, and all the variables
x^2+x-3.809=0
a = 1; b = 1; c = -3.809;
Δ = b2-4ac
Δ = 12-4·1·(-3.809)
Δ = 16.236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{16.236}}{2*1}=\frac{-1-\sqrt{16.236}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{16.236}}{2*1}=\frac{-1+\sqrt{16.236}}{2} $
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